What is the maximum value of c such that the graph of the parabola y = (1/3)x^2 has at most one point of intersection with the line y = xc?PreAlgebra Graph y=2^ (1/x) y = 21 x y = 2 1 x Exponential functions have a horizontal asymptote The equation of the horizontal asymptote is y = 0 y = 0 Horizontal Asymptote y = 0 yCompute the volume under the graph of 2 2 6 3 z y x = − and above the rectangle 1 ≤ x ≤ 1 and 1 ≤ y ≤ 3 in the xyplane (10 pts) 6 Calculate the integral 2 2 0 0 0 (2) − − y z z x y dxdydz (5 pts) 7 Sketch AND describe the region of integration of 2 2 2 4 16 2 0 16 ( ,, ) y y f x y
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The graph of mathx^2(y\sqrt3{x^2})^2=1/math is very interesting and is show below using desmosKnowing this, and the rules of exponents, we can deduce that y = (x) 4 is equivalent to y = (x 1 2) 4 thus, the graph would simply be that of y = x 4 2 or y = x 2, which is a parabola However, given that math is not always reversible as this, it should be noted that the bounds of y = (x) 4 are not the same as that of y = x 2, because of the inclusion of the square root The square root does notScience A Graph Shows Distance On The Vertical Axis And Time On The Horitzonal Axis If The Speed Is Steadily Increasing What Will The Line Representing Speed Look Like On The Graph?
We are given the function {eq}y=\frac{1}{2}x5 {/eq} We want to graph the given function So, we have Solution The given function is in the slope intercept form {eq}y=mxb {/eq} where m is theGraph x^2y=1 x2 − y = 1 x 2 y = 1 Solve for y y Tap for more steps Subtract x 2 x 2 from both sides of the equation − y = 1 − x 2 y = 1 x 2 Multiply each term in − y = 1 − x 2 y = 1 x 2 by − 1 1 Tap for more steps Multiply each term in − y = 1 − x 2 y = 1 x 2 by − 1 1We will use 1 and 4 for x If x = 1, y = 2(1) 6 = 4 if x = 4, y = 2(4) 6 = 2 Thus, two solutions of the equation are (1, 4) and (4, 2) Next, we graph these ordered pairs and draw a straight line through the points as shown in the figure We use arrowheads to show that the line extends infinitely far in both directions
Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyAn example of how to graph a linear equation in slope intercept form by interpreting its slope and yinterceptIf y = mx bm = slope, b = yinterceptThe simple way to graph y = x1 is to generate at least two points, put those on your graph paper and draw a straight line through them Here's how you geneate the required points Use your equation, y = x1 and choose an integer for x, say x=2, and substitute this into your equation to find the corresponding value of y y = 2 1 y = 1
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Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicUse the distributive property to multiply y by x 2 1 Add x to both sides Add x to both sides All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions,Sin (x)cos (y)=05 2x−3y=1 cos (x^2)=y (x−3) (x3)=y^2 y=x^2 If you don't include an equals sign, it will assume you mean " =0 " It has not been well tested, so have fun with it, but don't trust it If it gives you problems, let me know Note it may take a few seconds to finish, because it has to do lots of calculations
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Subtract y from both sides x^ {2}x1y=0 x 2 x 1 − y = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 1 for b, and 1y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} This equation is in standard form a x 2 b x c = 0 Since y^2 = x − 2 is a relation (has more than 1 yvalue for each xvalue) and not a function (which has a maximum of 1 yvalue for each xvalue), we need to split it into 2 separate functions and graph them together So the first one will be y 1 = √ (x − 2) and the second one is y 2 = −√ (x − 2)Y=x3x212x No solutions found Rearrange Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation y(x^3x^212*x)=0
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Cos(x^2) (x−3)(x3) Zooming and Recentering You can clickanddrag to move the graph around If you just clickandrelease (without moving), then the spot you clicked on will be the new center To reset the zoom to the original click on the Reset button Using "a" ValuesMath Input NEW Use textbook math notation to enter your math Try itSelect a few x x values, and plug them into the equation to find the corresponding y y values The x x values should be selected around the vertex Tap for more steps Substitute the x x value − 1 1 into f ( x) = √ − x 1 f ( x) = x 1 In this case, the point is ( − 1, ) ( 1, )
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We see that it's good enough for either factor on the left to be 0, so if y =x or y = x, we get a point on the graph (a) Using this reasoning, sketch the graph (y – x²) (y – e*) = 0 (b) Give an equation for the graph shown (a line of slope 1 passing through the middle of the unit circle) 2Extended Keyboard Examples Upload Random Examples Upload Random So y is always positive As x becomes smaller and smaller then 1/(1x^2) > 1/1 = 1 So lim_(x>0) 1/(1x^2)=1 As x becomes bigger and bigger then 1x^2 becomes bigger so 1/(1x^2) becomes smaller lim_(x>oo) 1/(1x^2)=0 color(blue)("build a table of value for different values of "x" and calculate the appropriate values of y
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Algebra Graph y=x^ (1/2) y = x1 2 y = x 1 2 Graph y = x1 2 y = x 1 2For y = 3x6 y = 3 x 6 , the slope is 3 3 and the yintercept is at y= 6 y = 6 or at point (0,6) ( 0, 6) To graph each equation, we have to locate first the yintercept Then, we will use the Find the area of the region bounded by the parabola y=x^2, the tangent line to this parabola at (1,1) and the xaxis I don't really get what this question is asking It looks like the area of right triangle to metry the graph, Calculus The graph of f(x)=(axb)/(x^2 5x 4) has a horizontal tangent line at (2, 1) Find a and b
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Question y=(x1)(x 1)(x2) 14 The graph in the xyplane of the equation above contains the point (a,b) 1sas1 which of the following is NOT a possible value of b?Yintercept of (0,1) Slope of (3/2) Slope=(Change in y)/(Change in x)=3/2 Starting at the yintercept (0,1) Next x point 02=2 Next y point13=2Experts are tested by Chegg as specialists in their subject area We review their content and use your feedback to keep the quality high Solution Horizontal ri View the full answer Transcribed image text Below is the graph of y C) X2 Translate it to become the graph of y= 3 y 74 х 6 5 4 3 2 (0, 1) 1 6 5
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Explanation We are given the quadratic function y = f (x) = (x 2)2 For the family of quadratic functions, the parent function is of the form y = f (x) = x2 When graphing quadratic functions, there is a useful form called the vertex form y = f (x) = a(x −h)2 k, where (h,k) is the vertex Data table is given belowGraph y= (x1)^22 y = (x − 1)2 2 y = ( x 1) 2 2 Find the properties of the given parabola Tap for more steps Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k a = 1 a = 1 h = 1 h = 1 k = 2 k = 2See the vertex on each "y" function below, it moves an increment of 1 from 0 of the x
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Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicFree functions and graphing calculator analyze and graph line equations and functions stepbystep This website uses cookies to ensure you get the best experience By using this website, you agree to our Cookie Policy domain\y=\frac{x^2x1}{x} range\y=\frac{x^2x1}{x} asymptotes\y=\frac{x}{x^26x8} extreme\points\y=\frac{x^2x1The coefficient of \(x^3\) is positive, so for large \(x\) we get a positive \(y\), in which case (a) cannot be the graph When \(x=0\), \(y=1\), so the \(y\)intercept is \(1\) and therefore (b) cannot be the graph
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The graph xy = 2x 2y is shown in green, is asymptotic to the graph graph y = 2 and x =2, and crosses the yaxis at 0 The graph of xy = 2x 2y 1 is shown in red and crosses the yaxis at 5which is onehalf of the constant The graph xy = 2x 2y 3 is shown in blue and crosses the yaxis at 15, and this is onehalf the constantSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreThe quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}8xy1=0 x 2 8 x − y − 1 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 8 for b, and 1y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a}
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The graph of y=(2)^x is then What you don't see in the picture is that the graph has a large number of "holes" The only points on the graph have first coordinate x=p/q where p and q are integers with no common factors other than 1 and q is odd If p is even the point with first coordinate x=p/q is on the "upper" curve and is p is odd theX^2 2 y^2 = 1 Natural Language;This takes the graph of y = x^2 and moves each point 2 to the left y=(x3)^2 This takes the graph of y = x^2 and moves each point 3 to the left===== Cheers, Stan H Answer by jojo(1513) (Show Source) You can put this solution on YOUR website!
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Use "x" as the variable like this Examples sin(x) 2x−3;Who are the experts?A Graph y = e x and y = 1 x x 2 /2 in the same viewingrectangle b Graph y = e x and y = 1 x x 2 /2 x 3 /6in the sameviewing rectangle c Graph y = ex and y = 1 x x 2 /2 x 3 /6 x 4 /24 in thesame viewing rectangle d Describe what you
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Draw the graph of y = x^2 3x – 4 and hence use it to solve x^2 3x – 4 = 0 y^2 = x 3x – 4 asked in Algebra by Darshee ( 491k points) algebraBeyond simple math and grouping (like "(x2)(x4)"), there are some functions you can use as well Look below to see them all They are mostly standard functions written as you might expect You can also use "pi" and "e" as their respective constants Please Graph as y = (2x)/(x4) by establishing a few data points with random values of x and noting the asymptotic limits at y=2 and x=1 The asymptotic limit x=1 should be obvious from the expression (since division by 0 is undefined) y=(2x)/(x1) is equivalent to y=2/(11/x) provided we ignore the special case x=0 As x rarr oo color(white)("XXXX")1/x rarr 0 and color(white)("XXXX")y=2/(11/x) rarr 2/1 = 2
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A sketch of the graph \(y=x^3x^2x1\) appears on which of the following axes?Equation of a straight line is Y=mx c Now , for your equation Y=X1X2 or Y= 2X3 so equating it with the equation of a straight line , m=2 & c=3 Hence, the graph will be a straight line for this equation Start putting X value from zero & plot the Y values and you will get the Coordinates of X,Y which will determine the straight line graphDemonstration of how to graph an equation in slope intercept form interpreting the slope at the coefficient of x and the constant term as the yinterceptSlo
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Graph the parabola, y =x^21 by finding the turning point and using a table to find values for x and ySubtracting x 2 from itself leaves 0 \left (y\sqrt 3 {x}\right)^ {2}=1x^ {2} ( y 3 x ) 2 = 1 − x 2 Take the square root of both sides of the equation Take the square root of both sides of the equation y\sqrt 3 {x}=\sqrt {1x^ {2}} y\sqrt 3 {x}=\sqrt {1x^ {2}} y 3 x = 1 − x 2 y 3 x = − 1 − x 2In this math video lesson I show how to graph y=(1/2)x2 The equation in this video is in slopeintercept form, y=mxb, and is a common way to graph an equ
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